Convergence of Deterministic IFS<

Now we shall prove that if all the Ti are euclidean contractions, then T is a Hausdorff contraction.
First we need a Lemma.
Lemma 1 For all compact sets A, B, C, and D in the plane,
h(A ∪ B, C ∪ D) ≤ max{h(A,C),h(B,D)}
Here is the proof of the lemma.
Now we are ready to prove the the proposition.
Prop. 2 For all compact sets A and B in the plane,
h(T (A),T (B)) ≤ r⋅h(A,B)
where r = max{r1,...,rN}, and ri is the euclidean contraction factor of Ti.
Proof
h(T (A),T (B))
= h(T1(A) ∪ T2(A) ∪ ... ∪ TN(A), T1(B) ∪ T2(B) ∪ ... ∪ TN(B))
= h(T1(A) U (T2(A) ∪ ... ∪ TN(A)), T1(B) ∪ (T2(B) ∪ ... ∪ TN(B)))
separating T1(A) from Ti(A), and T1(B) from Ti(B)
≤ max{h(T1(A),T1(B)), h(T2(A) ∪ ... ∪ TN(A), T2(B) ∪ ... ∪ TN(B))}
by the Lemma
≤ max{h(T1(A),T1(B)), h(T2(A),T2(B)), ..., h(TN(A),TN(B))}
keep applying the Lemma
≤ max{r1⋅h(A,B), r2⋅h(A,B), ..., rN⋅h(A,B)}
by Prop. 1
= max{r1, r2, ..., rN}⋅h(A,B)
= r⋅h(A,B)

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