Box-Counting Dimension

Practice Problem 4 Answer

From the relation N(1/3n) = 6n, we compute the box-counting dimension
db = limn→∞Log(N(1/3n))/Log(1/(1/3n))
= limn→∞Log(6n)/Log(3n)
= limn→∞(n⋅Log(6))/(n⋅Log(3))
= Log(6)/Log(3) ≈ 1.63093.

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