Box-Counting Dimension

Practice Problem 4 Answer

We can cover this fractal with 6 boxes of side 1/3. Self-similarity guarantees we need 36 boxes of side 1/9, and in general, 6n boxes of side 1/3n.
   
From this, we fill in the table
rn N(rn) 1/rn Log(1/rn) Log(N(rn))
1 1 1 0 0
1/3 6 3 .477 .778
1/9 36 9 .954 1.556
1/27 216 27 1.431 2.334
1/81 1296 81 1.908 3.113
1/243 7776 243 2.386 3.891
Here is the log-log plot.
Here we compute the exact value of the dimension.

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