| (x, y) | = T3T2T1(x, y) = T3T2(x/2, y/2) |
| = T3(x/4 + 1/2, y/4) = (x/8 + 1/4, y/8 + 1/2) | |
| so | |
| x = x/8 + 1/4 and y = y/8 + 1/2 | |
| Solving for x and y gives (x, y) = (2/7, 4/7). | |
| Solving the fixed point equations gives the coordinates of each point. For example, | ||||||||||
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| Similar calculations show | ||||||||||
| (1/7, 2/7) is the fixed point of T1T3T2 | ||||||||||
| and | ||||||||||
| (4/7, 1/7) is the fixed point of T2T1T3 | ||||||||||
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Return to Cyclic IFS.