| As a test of familiarity with the mechanics of logarithms, find the error in this calculation: |
| ds = Log(4)/Log(2) |
| Cancel the Logs to obtain |
| ds = 4/2 = 2. |
| This is the right answer, although the method is flawed. The correct method is |
| Log(4)/Log(2) = Log(22)/Log(2) = 2⋅Log(2)/Log(2) = 2 |
| That is, instead of cancelling Logs, which we can't do, we cancel Log(2)s, which we can do. Can you find other ratios for which the analogous (wrong) calculation gives the right answer? |
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