f(alpha) exercise 4 solution

Recall in the oblique asymptotes question of the tau(q) curve, we observed alphamin = 1.15 and alphamax = 4.32.
In exercise 3 we saw
f(1.35) = 1.06 (q=3), f(1.72) = 1.72 (q=1), and f(3.48) = 1.45 (q=-1).
As before, we calculate tau(0) = 2 and alpha(0) = 2.38, so f(alpha) = 2.38*0 + 2 = 2.
Here is a plot of these points.

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