Variation on the fifth example

Here is the fractal of the fifth example, but modified so each piece is scaled by r = 1/4. To emphasize the scaling, each piece is surrounded by the unit square, scaled by r = 1/4.
What is the similarity dimension of this fractal? Applying the formula ds = Log(N)/Log(1/r), we obtain
ds = Log(4)/Log(4) = 1.
This is the dimension of a line, yet this fractal doesn't look at all like a line.
However, note the formula for ds does not depend on the placement of the pieces, only on their number and size.
So suppose we move some of the pieces (without introducing any overlaps).
Can appropriate repositioning of the pieces make this dimension calculation match our intuitions? Let us see.
Click the picture to animate.

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