We'll try to compute the area of the Koch curve by covering it with isosceles triangles (suggested by the general shape of the Koch curve). |
Using smaller and smaller triangles should give a better estimate of the area of the Koch curve. |
First, cover the Koch cuve with a single triangle. |
This triangle has base length 1 and altitude sqrt(3)/6 (from the Pythagorean theorem), |
hence area |
A0 = (√3)/12. |
Certainly, the area of the Koch curve is less than A0. |
Here is the second approximation.
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