Box-Counting Dimension

Practice Problem 1 Answer

We can cover this fractal with 5 boxes of side 1/3. Self-similarity guarantees we need 25 boxes of side 1/9, and in general, 5n boxes of side 1/3n.
   
From this, we fill in the table

rn N(rn) 1/rn Log(1/rn) Log(N(rn))
1 1 1 0 0
1/3 5 3 .477 .699
1/9 25 9 .954 1.398
1/27 125 27 1.431 2.097
1/81 625 81 1.908 2.796
1/243 3125 243 2.386 3.495

Here is the log-log plot.
Here we compute the exact value of the dimension.

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