Box-Counting Dimension of a Gasket

From the relation N((1/2)n) = 3n we can compute the exact value of db for the gasket.
db = limrn→0Log(N(rn)) / Log(1/rn)
= limn→∞Log(N(rn)) / Log(1/rn)
= limn→∞Log(N((1/2)n)) / Log(1/((1/2)n))
= limn→∞Log(3n) / Log(2n)
= limn→∞(n⋅Log(3)) / (n⋅Log(2))
= Log(3) / Log(2) ≈ 1.58996

Return to Box-Counting Dimension of a Gasket.